Complete Question
The complete question is shown on the first and second uploaded image
Note : The resistance is R = 147 Ohms
Answer:
The current density in terms of resistivity is [tex]J = \frac{E}{\rho}[/tex]
The current is [tex]I = 176 *10^{-3} \ A[/tex]
Explanation:
From the question we are told that
The length of the wire is [tex]L = 2.75 \ m[/tex]
The radius of the circular cross-sectional area is [tex]r = 1.76 \ mm = 0.00176 m[/tex]
The electric field strength is E =9.41 V/m
Generally the current density is mathematically represented as
[tex]J = \frac{E}{\rho}[/tex]
Here [tex]\rho[/tex] is the resistivity of the wire which is mathematically represented as
[tex]\rho = \frac{R * A}{L}[/tex]
So
[tex]J = \frac{EL }{RA}[/tex]
Here A is the cross-sectional area which is mathematically represented as
[tex]A =\pi r^2[/tex]
So
[tex]J = \frac{EL }{R * \pi r^2 }[/tex]
Generally the current density can also be mathematically represented as
[tex]J = \frac{I}{A}[/tex]
So
[tex]\frac{EL }{RA} = \frac{I}{A}[/tex]
=> [tex]I = \frac{EL}{R}[/tex]
=> [tex]I = \frac{9.41 2.75}{147 }[/tex]
=> [tex]I = 176 *10^{-3} \ A[/tex]
