Answer:
The magnification is [tex]m = 0.3674[/tex]
Explanation:
From the question we are told that
The power of the lens is [tex]P = -4.00 D(dioptre)[/tex]
Generally [tex]1 dioptre = 1 \ meter[/tex]
The object distance is [tex]u = -43 \ cm[/tex] the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )
Generally the focal length is mathematically represented as
[tex]f = \frac{1}{P}[/tex]
=>[tex]f = \frac{1}{4.00 }[/tex]
=> [tex]f = 0.25 \ m[/tex]
converting to cm
=> [tex]f = 0.25 \ m = 0.25 * 100 = 25 \ cm[/tex]
Generally from lens equation we have that
[tex]\frac{1}{f} +\frac{1}{v} -\frac{1}{u}[/tex]
=> [tex]\frac{1}{25} +\frac{1}{v} -\frac{1}{-43}[/tex]
=> [tex]v = -15.8 \ cm[/tex]
Generally the magnification is mathematically represented as
[tex]m = \frac{v}{u}[/tex]
=> [tex]m = \frac{- 15.8}{-43}[/tex]
=> [tex]m = 0.3674[/tex]
