Answer:
The value is [tex]T =260.33 \ F[/tex]
Explanation:
From the question we are told that
The the peak wavelength is [tex]\lambda_p = 660 nm = 660 *10^{-9} \ m[/tex]
Generally according to the Wien's displacement law
[tex]\lambda_p * T = 2.898*10^{-3} \ m \cdot K[/tex]
Here T is the approximate surface temperature of this star in K so
[tex]660*10^{-9} * T = 2.898*10^{-3} \ m \cdot K[/tex]
=> [tex]T = 4091 \ K[/tex]
Converting to Fahrenheit ,
[tex]T = [400 - 273.15 ] * \frac{9}{5} + 32[/tex]
=> [tex]T =260.33 \ F[/tex]
