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A truck is descending a winding mountain road. When the truck is 1480 m above sea level and traveling 15 m/s, its brakes fail. What is the maximum possible speed of the truck at the foot of the mountain 550 m above sea level

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Answer:

The maximum possible speed of the truck at the foot of the mountain at 550 m above sea level is 135.91 [tex]\frac{m}{s}[/tex]

Explanation:

Mechanical energy is the ability of a body to generate motion and perform mechanical work.

In other words, mechanical energy is that related to both the position and the movement of bodies.

Mechanical energy is calculated by:

Em = Ep + Ec

where Em is the mechanical energy (J), Ep the potential energy (J) and Ec the kinetic energy (J).

The mechanical energy of a body remains constant when all the forces acting on it are conservative.

Potential energy refers to the position of a mass in space and is calculated by:

Ep = m • g • h

where m is the mass (kg), g the gravity of the Earth (9.81 [tex]\frac{m}{s^{2} }[/tex]) and h is the height (m)

Kinetic energy is the energy that an object has due to its movement and its expression for the calculation is:

Ec = ½ m • v²

Where m is the mass (Kg) and v the speed (m/s).

The truck would have  the maximum possible speed if friction were ignored. Then:

So the forces are conservative and the mechanical energy is constant. So:

Em initial= Em  final

So:

Ep initial + Ec initial= Ep final + Ec final

m • g • h  initial + ½ m • (v initial)² = m • g • h  final + ½ m • (v final)²  [mass and gravity remain constant]

As the mass m is found in all terms, they can be simplified and it is obtained:

g • h  initial + ½ • (v initial)² = g • h  final + ½ • (v final)²  

Taking as a reference the zero of the potential energy at sea level and isolating the value of vf, you obtain the expression:

[tex]vfinal=\sqrt{(v initial)^{2} +2*g*(h initial - h final)}[/tex]

Being:

  • v initial= 15 [tex]\frac{m}{s}[/tex]
  • g= 9.81 [tex]\frac{m}{s^{2} }[/tex]
  • h initial= 1480 m
  • h final= 550 m

and replacing:

[tex]vfinal=\sqrt{(15 \frac{m}{s} )^{2} +2*9.81 \frac{m}{s^{2} } *(1480 m - 550 m)}[/tex]

you get:

v final= 135.91 [tex]\frac{m}{s}[/tex]

The maximum possible speed of the truck at the foot of the mountain at 550 m above sea level is 135.91 [tex]\frac{m}{s}[/tex]

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