Answer:
10 seconds
Explanation:
Step one:
initial velocity= 0m/s
acceleration a= 4m/s^2
distance S= 200m
Step two:
from the equation of motion
S=ut+1/2at^2
substituting our data we have
200=0*t+1/2*4*t^2
200=2t^2
divide both sides by 2
100=t^2
square both sides
t=√100
t=10 seconds
it will take 10 seconds