Answer:
The value is [tex]P = 29400 \ Pa[/tex]
Explanation
From the question we are told that
The width of the pool is [tex]w = 9.0 \ m[/tex]
The length is [tex]l = 24.0 \ m[/tex]
The depth is [tex]d = 3.0 \ m[/tex]
Generally the pressure is mathematically represented as
[tex]P = \rho * g * d[/tex]
here [tex]\rho = 1000 \ kg / m^3[/tex] the density of water
=> [tex]P = 1000 * 9.8 * 3[/tex]
=> [tex]P = 29400 \ Pa[/tex]
