Answer:
The value is [tex]P = 892.7 \ atm[/tex]
Explanation:
From the question we are told that
The depth of the bottom of the trench is [tex]d = 11.0 \ km =11000 \ m[/tex]
The depth considered is [tex]h = 9.2 \ km = 9200 \ m[/tex]
Generally the pressure is mathematically represented as
[tex]P = \rho * g * h[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg/m^3[/tex]
=> [tex]P = 1000 * 9.8 * 9200[/tex]
=> [tex]P = 9.016*10^{7} \ Pa[/tex]
Converting to atmosphere
=> [tex]P = \frac{9.016*10^{7} }{101*10^{3}}[/tex]
=> [tex]P = 892.7 \ atm[/tex]
