Answer:
The value is [tex]\frac{n}{t} = 4.83 *10^{19} \ photons / s[/tex]
Explanation:
From the question we are told that
The power rating of the bulb is [tex]P = 160 \ W[/tex]
The frequency is [tex]f = 5.00 *10^{14} \ Hz[/tex]
The percentage of the input power that is emitted as visible light is [tex]\eta = 10\% = 0.10[/tex]
Generally the amount of power emitted as visible light is mathematically represented as
[tex]P_l = 0.10 * P_i[/tex]
=> [tex]P_l = 0.10 *160[/tex]
=> [tex]P_l = 16 \ W[/tex]
Generally the amount of energy emitted as light is mathematically represented as
[tex]E = n * h * f[/tex]
Here n is the number of photon , h is the Planks constant with value [tex]h = 6.625*10^{-34} \ J\cdot s[/tex]
Generally this power emitted as visible light is mathematically represented as
[tex]P_l = \frac{E}{t}[/tex]
=> [tex]P_l = \frac{E}{t} = \frac{nhf}{t}[/tex]
=> [tex]\frac{n}{t} = \frac{P_l }{hf}[/tex]
=> [tex]\frac{n}{t} = \frac{16 }{6.625 *10^{-34}* (5.00*10^{14})}[/tex]
=> [tex]\frac{n}{t} = 4.83 *10^{19} \ photons / s[/tex]
