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2090 J of heat energy are removed from 40 g of a silvery metal at 81.7°C. The temperature falls to 30°C. According to the chart below which metal would it most likely be? (Show work!) METAL. SPECIFIC HEAT (J/goC) -aluminum = 0.90 -magnesium = 1.01 -silver = 0.234 -tin = 0.220 -zinc = 0.386

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Answer:

Magnesium would be the metal

Explanation:

The heat involved in a physicochemical process follows the formula:

Q = m×C×ΔT

Where Q is heat involved,

m is mass of substance,

C is specific heat of the susbtance

And ΔT change in temperature

We can solve por specific heat of the solution:

C = Q / m*ΔT

Replacing the values of the problem:

C = 2090J / 40g*(81.7°C-30°C)

C = 1.01J/g°C

This specific heat is the specific heat of Magnesium. Thus:

Magnesium would be the metal

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