Hong the trainer has two solo workout plans that he offers his clients: Plan A and Plan B. Each client does either one or the other (not both). On Friday there were 4 clients who did Plan A and 8 who did Plan B. On Saturday there were 2 clients who did Plan A and 3 who did Plan B. Hong trained his Friday clients for a total of 9 hours and his Saturday clients for a total of 4 hours. How long does each of the workout plans last?

Respuesta :

Answer:

Session A = 1.25 hours

Session B = 0.5 hours

Step-by-step explanation:

Given

Plans: A and B

Friday can be expressed as: 4A + 8B

Saturday can be expressed as: 2A + 3B

Total Time:

Friday = 9 hours

Saturday = 4 hours

Required

Determine time for each session (A and B)

The question illustrates simultaneous equation and the equations are;

[tex]4A + 8B = 9[/tex]

[tex]2A + 3B = 4[/tex]

Multiply the second equation by 2

[tex]2(2A + 3B = 4)[/tex]

[tex]4A + 6B = 8[/tex]

Subtract this from the first equation:

[tex](4A + 8B = 9) - (4A + 6B = 8)[/tex]

[tex]4A - 4A + 8B -6B = 9 - 8[/tex]

[tex]8B -6B = 1[/tex]

[tex]2B = 1[/tex]

Solve for B

[tex]B= \frac{1}{2}[/tex]

[tex]B = 0.5\ hours[/tex]

Substitute [tex]B= \frac{1}{2}[/tex] in [tex]2A + 3B = 4[/tex]

[tex]2A + 3(\frac{1}{2}) = 4[/tex]

[tex]2A + \frac{3}{2} = 4[/tex]

Solve for 2A

[tex]2A = 4 - \frac{3}{2}[/tex]

[tex]2A = \frac{8 - 3}{2}[/tex]

[tex]2A = \frac{5}{2}[/tex]

Solve for A

[tex]A = \frac{5}{2} * \frac{1}{2}[/tex]

[tex]A = \frac{5}{4}[/tex]

[tex]A = 1.25\ hours[/tex]

Q&A Education