Answer:
1373.98 MPa.
Explanation:
It is given that,
The modulus of resilience of a steel alloy, U = 4.56 MPa
We need to find the strain at the yield point. The relation for the modulus of resilience is given by :
[tex]U=\dfrac{\sigma^2}{2E}[/tex]
Where
[tex]\sigma[/tex] is the yield strength
E is Modulus of Elasticity, for steel, E = 207 × 10³ MPa
[tex]\sigma=\sqrt{2UE} \\\\\sigma=\sqrt{2\times 4.56\times 207\times 10^3} \\\\\sigma=1373.98\ MPa[/tex]
So, the strain at the yield point is 1373.98 MPa.
