If a right triangle has its two other angles labeled as 3x + 10 and 5x + 16, find the
measure of each angle.
The angle marked as 3x + 10 would measure
I
degrees.
The angle marked as 5x + 16 would measure
degrees.

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Sum of the interior angles of any triangle equal 180 degrees .

Thus ;

[tex](3x + 10) + (5x + 16) + 90 = 180 \\ [/tex]

Subtract sides 90

[tex](3x + 10) + (5x + 16) + 90 - 90 = 180 - 90 \\ [/tex]

Simplification

[tex](3x + 10) + (5x + 16) = 90[/tex]

[tex]3x + 10 + 5x + 16 = 90[/tex]

Collect like terms

[tex]3x + 5x + 10 + 16 = 90[/tex]

[tex]8x + 26 = 90[/tex]

Subtract sides 26

[tex]8x + 26 - 26 = 90 - 26[/tex]

[tex]8x = 64[/tex]

Divide sides by 8

[tex] \frac{8x}{8} = \frac{64}{8} \\ [/tex]

[tex]x = 8[/tex]

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So ;

The angle marked as 3x + 10 would measure 34° degrees.

[tex]3(8) + 10 = 24 + 10 = 34[/tex]

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And ;

The angle marked as 5x + 16 would measure 56° degrees.

[tex]5(8) + 16 = 40 + 16 = 56[/tex]

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Done...

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