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A pivot at the 35cm mark supports a meter stick. It is brought into a balance by a 0.85N weight suspended at the 5.5cm mark.compute the weight of the meter stick.

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Oceans

Answer:

2.52N

Explanation:

according to law of moments ,

F1L1=F2L2 ,where the forces are in equilibrium .

0.85(44.5)= 15F2

that is , taking their distances from 50cm point

37 .825=15F2

37.825÷15= F2

2.52N = F2

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