The magnitude of a uniform electric field between two plates is about 1.7 × 106N/C. If the distance
between these plates is 1.5 cm, find the potential difference between the plates

Respuesta :

Answer:

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9^10^6 N/C * 0.015 m

V = 1.93 * 10^9 V

The units don't agree in any simple way, but the formula is correct, and it does work.

Explanation:

V = 1.93 * 10⁹ V

What is potential difference?

The electric potential difference is the difference in electric potential (V) between the final and the initial location when work is done upon a charge to change its potential energy.

The electrical potential difference between the two plates is expressed as V = E d ,

The electric field strength times the distance between the plates.

The units in this expression are Newtons/coulomb times meters, which gives the final units Joules/coulomb.

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9*10⁶ N/C * 0.015 m

V = 1.93 * 10⁹ V

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