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The diagram shows the trajectory of a ball that is thrown horizontally from the top of a building. The ball’s vertical and horizontal velocity vectors, along with the resultant vectors, are also indicated. If the ball takes 3.0 s to reach the ground, what is the ball’s vertical speed by the time it reaches the ground?

Respuesta :

MathPhys

Answer:

29.4 m/s

Explanation:

The ball is thrown horizontally, so the initial vertical velocity is 0 m/s.

The ball is in free fall, so it accelerates downward at -9.8 m/s².

After 3 seconds, the vertical velocity is:

v = at + vâ‚€

v = (-9.8 m/s²) (3 s) + 0 m/s

v = -29.4 m/s

The vertical speed is 29.4 m/s.

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