Respuesta :
Answer:
If you play this game once (and it costs you nothing to play), the expected amount of money you will win is:
$8.
Step-by-step explanation:
a) Data and Calculations:
The probability for the result to be 1 or 2 = 33.33% (100/6 * 2)
The probability for the result to be 3, 4, or 5 = 50% (100/6 * 3)
The probability for the result to be 6 = 16.67% (100/6 * 1)
Data Table:
Event Probability Value Won
The result is 1 or 2 33.33% $0
The result is 3, 4 or 5 50.00% $4.00
The result is 6 16.67% $36.00
Expected Value:
Event Probability Value Expected Value
The result is 1 or 2 33.33% $0 $0 ($0 * 33.33%)
The result is 3, 4 or 5 50.00% $4.00 $2.00 ($4 * 50%)
The result is 6 16.67% $36.00 $6.00 ($36 * 16.67%)
Total expected amount of money = $8.00
Using the discrete probability principle, the expected value for the amount of money which could be won ls $8.00
- Sample space = (1, 2, 3, 4, 5, 6)
- P(1 or 2) = 2/6 = 1/3 = 0.33
- P(3,4, or 5) = 3/6 = 1/2 = 0.5
- P(6) = 1/6 = 0.1667
X : ____ $0 _____ $4 _____ $36
P(X) : __ 0.333 ___ 0.5 ____ 0.1667
The expected value ls defined thus :
- Σ[(X × p(X)]
E(X) = (0 × 0.333) + (4 × 0.5) + (36 × 1/6)
E(X) = 0 + 2.0 + 6
E(X) = $8.0
Therefore, the expected amount to be won in the long run is $8.0
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