Answer:
Mass = 88.12 g
Explanation:
Given data:
Mass of iron oxide = 126 g
Mass of iron formed = ?
Solution:
Chemical equation:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Number of moles of iron oxide:
Number of moles = mass/molar mass
Number of moles = 126 g/ 159.69 g/mol
Number of moles = 0.789 mol
Now we will compare the moles of iron with iron oxide.
Fe₂O₃ : Fe
1 : 2
0.789 : 2/1×0.789 = 1.578 mol
Mass of iron:
Mass = number of moles ×molar mass
Mass = 1.578 mol × 55.84 g/mol
Mass = 88.12 g
The mass of iron formed from 126 grams of iron oxide has been 88.126 grams.
According to the balanced chemical equation, 1 mole of iron oxide reacts with 3 moles of carbon monoxide to form 2 moles of iron and 3 moles of carbon dioxide.
The equation gives:
1 mole iron oxide = 2 moles iron
1 mole iron oxide = 159.69 grams
1 mole of iron = 55.845 grams.
2 moles of iron = 111.69 grams.
159.69 grams Iron oxide = 111.69 grams iron
126 grams iron oxide = 88.126 grams.
The mass of iron formed from 126 grams of iron oxide has been 88.126 grams.
For more information about the reduction, refer to the link:
https://brainly.com/question/13699873
