Answer:
E = 65.37×10⁻²² J
Explanation:
Given data:
Energy of photon = ?
Frequency of photon = 9.86×10¹² Hz
Solution:
Formula:
E = h.f
Here h is planck's constant its value is 6.63×10⁻³⁴ js.
E = 6.63×10⁻³⁴ js × 9.86×10¹² Hz
Hz = s⁻¹
E = 65.37×10⁻²² J
The energy of photon is 65.37×10⁻²² J.
