Answer:
Mass of water produced = 801 g
Explanation:
Given data:
Mass of water produced = ?
Mass of H₂ = 89 g
Mass of oxygen = 64 g
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass/molar moles
Number of moles = 89 g/ 2 g/mol
Number of moles = 44.5 mol
Number of moles of oxygen:
Number of moles = mass/molar moles
Number of moles = 64 g/ 2 g/mol
Number of moles = 32 mol
Now we will compare the moles of water with oxygen and hydrogen.
H₂ : H₂O
2 : 2
44.5 : 44.5
O₂ : H₂O
1 : 2
32 : 2/1×32 =64 mol
Number of moles of water produced by hydrogen are less thus it yield is limit by hydrogen.
Mass of water:
Mass = number of moles × molar mass
Mass = 44.5 mol × 18 g/mol
Mass = 801 g
