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In the absence of air resistance, from what height should the diver
jump so he hits the water at a speed of 24 m/s? (Set the air resistance
slider to none. Adjust the height slider so the diver hits the water with
a speed of 24 m/s. )

Respuesta :

Assuming initial is velocity is 0,
Vf^2= v0^2 +2a•x
Vf^2 =2 a•x
Vf^2/2a=x
24^2/2(-9.8)=x
576 / 96.04= 5.875 m
asuwafohjames

The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

The height of the player above the ground can be calculated using the formula below.

  • v² = u²+2gs................. Equation 1

Where:

  • v = final velocity of the diver
  • u = initial velocity of the diver
  • s = height from where the diver will fall
  • g = acceleration due to gravity.

From the question,

⇒ Given:

  • v = 24 m/s
  • u = 0 m/s
  • g = 9.8 m/s².

⇒ Substitute these values into equation 1

  • 24² = 0²+(2×9.8×s)

⇒ Solve for s.

  • s = 24²/(2×9.8)
  • s = 29.4 m

Hence, The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

Learn more about height: https://brainly.com/question/12446886

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