Respuesta :

Answer: 14

Explanation:

Force(normal)*coefficient

The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept

  • The minimum force required to start the block moving is 14 N

Reason:

The known parameter are;

The weight of the block, W = 35 N

The static friction of the surface of the table surface, [tex]\mu_s[/tex] = 0.40

Required:

To find the minimum force to start the block moving

Solution:

The force required to start the block moving is given by the frictional force that needs to be surpassed

Force required, F = Force of friction

Force of friction = Normal reaction × Coefficient of static friction

On a flat surface, the normal reaction = The weight of the object

Force of friction, [tex]F_f[/tex] = Weight of the object × Coefficient of static friction

Which gives;

[tex]F_f = W \times \mu_s[/tex]

[tex]F_f = 35 \, N \times 0.40 = 14 \, N[/tex]

Force required, F = Force of friction, [tex]F_f[/tex] = 14 N

The minimum force required to start the block moving, F = 14 N

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