Answer my math question I asked so many times I lost most of points by
Answer:
Step-by-step explanation:
Parabolas can be written in the form
[tex]y = a(x-h)^2+k[/tex]
The vertex is (h, k). The vertex in the graph is (5, 0).
so far, we have
[tex]y = a(x-5)^2+0\\y = a(x-5)^2[/tex]
The other points we are given are (6, 1), (7, 4), (8, 9)
[tex]9 = a(8-5)^2\\9 = a(3)^2\\9 = 9a\\a = 1\\\\4 = a(7-5)^2\\4 = a(2)^2\\4 = 4a\\a = 1\\\\1 = a(6-5)^2\\a = 1[/tex]
In vertex form
[tex]y = (x-5)^2\\y = x^2 - 10x + 25[/tex]