\begin{cases}b(1)=16\\\\ b(n)=b(n-1)+1 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ b(1)=16 b(n)=b(n−1)+1 ​ Find the 2^{\text{nd}}2 nd 2, start superscript, start text, n, d, end text, end superscript term in the sequence.

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Answer:

17

Step-by-step explanation:

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The second term in the sequence is 17.

What is arithmetic sequence?

An arithmetic sequence is sequence of integers with its adjacent terms differing with one common difference.

Given the nth term of a sequence to be b(n)=b(n-1)+1, where n is the number of terms of the sequence

If b(1) = 16... (1)

The second term of the sequence is generated for n= 2:

b(n)=b(n-1)+1

b(2)=b(2-1)+1

b(2) = b(1)+1... (2)

Substituting equation 1 into 2

b(2) = b(1)+1

b(2) = 16 + 1 = 17

Hence, The second term in the sequence is 17.

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