Find the size of the angle BAC in the following triangle:
Answer:
Step-by-step explanation:
Sin A=5/8=0.625
[tex]A=sin^{-1} (0.625) \approx 36.68 ^\circ \\\approx 36.7^\circ\\\approx 37^\circ[/tex]
Length:
Side A = 5 cm
Side B ~9.434 cm
Side C = 8 cm
... Perimeter: ~22.434
... Area: 20
Angle:
Angle ∠A = 32.005°
Angle ∠B = 90°
Angle ∠C = 57.995°