1. How is the attractive electrostatic force between a proton and an electron indicated in Coulomb's law?
the sum of the charges indicates a positive force

the product of the charges indicates a positive force

the product of the charges indicates a negative force

the sum of the charges indicates a negative force

2. One particle has a negative charge, while another particle is neutral. Which statement describes the electrostatic force between these two particles?
There would be no electrostatic force because the sum of the two charges is 0.

The electrostatic force is attractive due to the particle with negative charge.

There would be no electrostatic force because the product of the two charges is 0.

The electrostatic force is repulsive due to the particle with negative charge.

3. How would the electrostatic force change if Coulomb's law included a negative sign?
Like charges would repel, and opposite charges would attract.

It would not make a difference in the electrostatic force.

It would depend on the magnitude of the charges.

Like charges would attract, and opposite charges would repel.

What is the value and the direction of an electric field at a distance of 2.5 m from a +1 nC charge?

approximately 145 V/m directed away from the positive charge

approximately 145 V/m directed toward the positive charge

approximately 1.45 V/m directed away from the positive charge

approximately 1.45 V/m directed toward the positive charge

According to Coulomb's law the electrostatic force is directly proportional to the product of the charges and inversely proportional to the distance separating them.

According to Coulomb's law;

F =[tex]Kq1q2/r^2\\[/tex]

Where;

K = constant of Coulomb's law

q1 and q2 are the respective magnitudes of the charges

r = distance separating the charges

Hence,according to Coulomb's law, the product of the charges indicates a negative force.

According to Coulomb's law, for a negative charge, and a neutral particle, there would be no electrostatic force because the product of the two charges is 0. If Coulomb's law included a negative sign then Like charges would attract, and opposite charges would repel.

The electric field is given by the formula;

[tex]E = kq/r^2\\k= 9 * 10^9 Nm^2C-2\\q =1 * 10^-9 C\\r = 2.5 m\\E = 9 * 10^9 Nm^2C-2 * 1 * 10^-9 C/( 2.5 m)^2\\E = 1.45 V/m[/tex]

The direction of the electric field is 1.45 V/m directed away from the positive charge.

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