Respuesta :

kate3652

Answer:

[tex] - 3 \geqslant a[/tex]

Step-by-step explanation:

[tex]6 \geqslant - 6(a + 2)[/tex]

distribute -6 inside the parentheses

[tex]6 \geqslant - 6a - 12[/tex]

add 12 to both sides

[tex]18 \geqslant - 6a[/tex]

divide by -6 to isolate the variable

[tex] - 3 \geqslant a[/tex]

Answer:

-3<=a

Step-by-step explanation:

1. Get the -6 away, so multiply everything by -6.  6*-6 >= -6*-6(a+2)

2. This becomes -1 <= a+2   Since if you multiply or divide anything by a negative number, you have to reverse the inequality sign.

3. Subtract 2 to get a by itself    -1-2 >= a

4. This becomes -3 >= a   which is the right answer.

(Just so you know >=  and <=  means less than or equal to and more than or equal to.)  

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