Answer:
[tex]a=1.3\ m/s^2[/tex]
Explanation:
It is given that,
Initial velocity, u = 4 m/s
Final velocity, v = 6 m/s
Time, t = 1.5 s
We need to find the average acceleration of a sprinter during this period. We know that the rate of change of velocity of an object is equal to its acceleration. So,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{(6-4)\ m/s}{1.5\ s}\\\\a=1.33\ m/s^2[/tex]
So, the acceleration of the sprinter is [tex]1.33\ m/s^2[/tex]. Hence, the correct option is (d).
