The acceleration/deceleration of the truck is 11.56 m/s^2
Velocity = change in displacement/ time
Acceleration = change in velocity/ time.
The acceleration, velocity and distance travelled of a body is related by the equation below:
where v is the initial velocity
u is the final velocity
a is the acceleration, and
s is the distance travelled
From the data provided:
v = 0
u = 34 m/s
s = 50 m
a = ?
making a subject of the formula
a = -u^2/2s
a = - 34^2 / 2 × 50
a = -11.56 m/s^2
Therefore, the acceleration/deceleration of the truck is 11.56 m/s^2
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