really confused on how to approach this problem.
Step-by-step explanation:
For this Q, you should draw a triangle to help you with the values.
cos x =
[tex] \frac{ \sqrt{2} }{2} [/tex]
csc x =
[tex] \frac{2}{ \sqrt{2} } [/tex]
tan x = sin x/ cos x
= 1
cot x = 1
sec x =
[tex] \frac{ \sqrt{2} }{2} [/tex]
x = 45 degrees