The least-squares regression line yˆ=1.8−0.2x summarizes the relationship between velocity, in feet per second, and depth, in feet, in measurements taken for a certain river, where x represents velocity and y represents the depth of the river. What is the predicted value of y, in feet, when x=5?

It is 0.8 because since you have y=1.8-0.2x (which is in the form of y=mx+b); and you have the value that x=5, all that you have to do is plug in 5 into the X in the equation.

Here is shown work:

y=1.8-0.2x

y=1.8-0.2(5)

y=1.8-1

y=0.8

Hopefully this helps! :)

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fichoh fichoh · Answer 2 · 2021-09-23T12:29:49+02:00

The predicted depth value when the velocity value is 5 will be 0.8 feets

Given the regression model :

yˆ=1.8−0.2x

yˆ = Predicted value

x = velocity

To calculate the predicted depth, at a given velocity, x ;

Substitute the value of x and solve for yˆ in the equation

When x = 5

yˆ=1.8−0.2(5)

yˆ=1.8− 1.0

yˆ = 0.8

Therefore, the predicted depth value in feet is 0.8

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