Answer:
Q = 126.5 kJ
Explanation:
Given that,
Mass, m = 1210 g
Specific heat of water, c = 4.184 J/g°C
Initial temperature, [tex]T_i=20^{\circ} C[/tex]
Final temperature, [tex]T_f=45^{\circ} C[/tex]
We need to find the heat absorbed by water. The formula that is used to find the heat absorbed is given by :
[tex]Q=mc\Delta T[/tex]
Putting all the values in it we get :
[tex]Q=1210\ g\times 4.184\ J/g^{\circ} C\times (45-20)^{\circ} C\\Q=126566\ J\\\\\text{or}\\\\Q=126.5\ kJ[/tex]
So, the amount of heat absorbed is 126.5 kJ.