Using the formula Q = m x ^T x Cp, solve for energy, and round your answer to the correct number of sig figs and show all work:

1) How much heat is absorbed by 1210. g water (Cp = 4.184 J/g*C) when it is heated from 20*C to 45*C

Respuesta :

Answer:

Q = 126.5 kJ

Explanation:

Given that,

Mass, m = 1210 g

Specific heat of water, c =  4.184 J/g°C

Initial temperature, [tex]T_i=20^{\circ} C[/tex]

Final temperature, [tex]T_f=45^{\circ} C[/tex]

We need to find the heat absorbed by water. The formula that is used to find the heat absorbed is given by :

[tex]Q=mc\Delta T[/tex]

Putting all the values in it we get :

[tex]Q=1210\ g\times 4.184\ J/g^{\circ} C\times (45-20)^{\circ} C\\Q=126566\ J\\\\\text{or}\\\\Q=126.5\ kJ[/tex]

So, the amount of heat absorbed is 126.5 kJ.

Q&A Education