kmpayne5 kmpayne5

05-10-2020
Mathematics

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(4a−a3−3)+(2a3−5a2+8) find the sum

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johnso78390 johnso78390

05-10-2020

Answer: a3−5a2+4a+5

Step-by-step explanation:

4a+−a3+−3+2a3+−5a2+8

=(−a3+2a3)+(−5a2)+(4a)+(−3+8)

=a3+−5a2+4a+5

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