Answer:
$840
Explanation:
the question misses an important detail, number of motors.
I used 10 as the total number of cars. from the solution i believe you would be able to solve any other problem of this sort yourself.
n = 10
p = 1-probability of any 1 motor being defective
= 1-0.08
= 0.92
going further in solving this problem, i will use the binomial distribution
we have expected value as;
Σxp(x)
= $100 x p(of 100) - $100 x p(of losing 100)
= 100(0.92) - 100(0.08)
= 92 - 8
= $84
from here we multiply 84$ by n
remember n = Â total number of cars = 10
10 x $84
= $840