Answer:
2.38%
Step-by-step explanation:
Given that:
The population size involving numbers of treated and untreated seeds N Â = 10
the number of seeds that are treated which are observed = 5
the number of seeds that sprouted 'n' = 4
Now, use the method of hypergeometric probability, we have the formula:
[tex]p(y) = \dfrac{(^r_y)(^{N-r}_{n-y})}{(^N_n)}[/tex]
∴
[tex]p(4) = \dfrac{(^5_4)(^{5}_{0})}{(^{10}_4)}[/tex]
[tex]p(4) = \dfrac{\dfrac{5!}{4!(5-4)!}* \dfrac{5!}{0!(5-0)!} }{\dfrac{10!}{4!(10-4)!} }[/tex]
[tex]p(4) = \dfrac{\dfrac{5!}{4!}* \dfrac{5!}{(5)!} }{\dfrac{10!}{4!(6)!} }[/tex]
[tex]p(4) = \dfrac{5*1 }{210}[/tex]
p(4) = 0.0238
p(4) = 2.38%