Answer:
1
Step-by-step explanation:
[tex][\frac{3a^{-2} b^6}{2a^{-1}b^5}] ^{2} \\=[1.5 a^{-2-(-1)} b^{6-5}]^2\\=[1.5a^{-2+1}b]^2\\=[1.5a^{-1}b]^2\\\\Substituting\ a=3,b=-2, we\ get,\\=[1.5*3^{-1}*-2]^2\\=[1.5*1/3*-2]^2\\=[1/2*-2]^2\\=[-1]^2\\=1[/tex]
