Answer:
The answer is "Option a and Option b".
Step-by-step explanation:
In the given question, the data value is missing which is defined in the attached file, please find it.
We have variance sample =[tex](S^2x, S^2y)[/tex] and the carariance sample = [tex]Sxy[/tex].
if "[tex]S^2x = 85.27, S^2y = 175.76, and \ \ Sxy = 116.25[/tex]" its sample coefficient correlation will be defined as follows:
[tex]\bold{r= \frac{Sxy}{\sqrt{S^2x \times S^2 y}} }\\\\[/tex]
[tex]= \frac{116.25}{\sqrt{85.23} \times \sqrt{175.76}} \\\\= \frac{116.25}{ 9.23 \times 13.25}\\\\= \frac{116.25}{122.29}\\\\=0.95[/tex]