Answer:
[tex]\huge\boxed{(1, -3)}[/tex]
Step-by-step explanation:
In order to find the solution to this system of equations, our goal is to get one variable on one side of the equation.
With the equations d [tex]10x-2y=16[/tex], and [tex]10x-2y=16[/tex], we know that we can multiply [tex]10x-2y=16[/tex] by -1 and the x terms will cancel out (as 10 - 10 = 0).
[tex]-1(10x-2y=16) = -10x + 6y = -16[/tex]
Now we add this equation to the first.
[tex]10x+9y=-17[/tex]
[tex]-10x+2y=-16[/tex]
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[tex]11y=-33[/tex]
Divide both sides by 11 and we get [tex]y=-3[/tex].
Now that we know the value of y, we can substitute it inside an equation and find the value of x. Let's substitute it inside [tex]10x-2y=16[/tex].
[tex]10x-2(-3)=16\\10x+6=16\\10x=10\\\\x=1[/tex]
So x = 1.
Hope this helped!
Hope this helped!
