14. I have an unknown volume of gas at a pressure of 1.2 atm and a temperature of 210 K. If I raise the pressure to 1.9 atm and decrease the temperature to 200 K, and measure the final volume to be 56 L, what was the initial volume of the gas? *
The law is given by the following equation: PV = nRT, where P = pressure, V = volume, n = number of moles, R is the universal gas constant, which equals 0.0821 L-atm / mole-K, and T is the temperature in Kelvin.
