contestada

what is the factored form of n^3 + 512?
A (n - 8) (n^2 + 8n+64)
B (n + 4)(n^2 - 4n + 128)
C (n - 4)(n^2 + 4n + 128)
D (n + 8)(n^2 - 8n + 64)

Respuesta :

jcherry99

Answer:

Step-by-step explanation:

n^3 + 512

512 = 8^3

So the factors are

(n + 8)(n^2 - nx + 64)

dodi00

Answer:

try D(n+8) (n^2'8n+64)

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