Given parameters:
Equation of the straight line;
y - 3 = [tex]\frac{-1}{2}[/tex](x -2)
We can determine the slope of any straight line from the equation of such lines.
Generally, a straight line has the formula;
y = mx + C
where y is the y-axis coordinate and x is the x-axis coordinate
m is the slope and c is the y-axis intercept
Now let us express the given equation in this format;
y - 3 = [tex]\frac{-1}{2}[/tex](x - 2)
Multiply both sides by 2;
2(y - 3) = -1(x -2)
2y -6 = -x + 2
Rearrange to the form y = mx + c
2y = -x + 2 + 6
2y = -x + 8
divide by 2;
y = [tex]\frac{-1}{2}[/tex]x + 4
y = mx + c
the slope is m and it is equal to [tex]\frac{-1}{2}[/tex]
