A 350-kg sailboat has an acceleration of 0.62 m/s2 at a angle of 64 degrees north of east find the magnitude and direction of the net force that acts on the sail boat

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Answer:

The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

Explanation:

Mechanical Force

The second Newton's law states the net force exerted by an external agent on an object of mass m is:

[tex]\vec F = m.\vec a[/tex]

Where [tex]\vec a[/tex] is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.

This means the net force and the acceleration have the same direction.

The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:

[tex]F=0.62 * 350=217\ N[/tex]

As stated above its direction is the same as the acceleration, thus:

The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

Newton second law of motion:

Here this law of motion should be applied

We know that

F = ma

Here m means the mass

And, the a means the acceleration

Since m is 350 kg

And, a is 0.62

so the net force should be

= 350 * 0.62

= 217 N

Also the direction should be the same

hence, The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.

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