Respuesta :

Answer:

3 and 4

Step-by-step explanation:

Consider perfect squares either side of 12, that is

9 < 12 < 16 , then

[tex]\sqrt{9}[/tex] < [tex]\sqrt{12}[/tex] < [tex]\sqrt{16}[/tex] , that is

3 < [tex]\sqrt{12}[/tex] < 4

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