Respuesta :

ShirIey

Answer:

Given -

  • Mass (m) = 3.5 kg
  • Acceleration (a) = 2.2 m/s²

To find -

  • External net force exerted on papaya.

Solution -

From the second law of motion i.e., F = MA

→ F = 3.5 × 2.2

→ 7.7 kg ms-²

Therefore, the external net force exerted on papaya is 7.7 kg m/s².

okpalawalter8

We have that  the external net force exerted is

F=7.7N

From the question we are told

the external net force exerted on a 3.5 kg papaya, which is being pushed across a table and has an acceleration of 2.2 m /s² to the left​

Generally the equation for the Force   is mathematically given as

[tex]F=ma\\\\Therefore\\\\\F=3.5*2.2\\\\F=7.7N[/tex]

Therefore

The external net force exerted is

F=7.7N

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