Respuesta :
Answer :
Part 1: The molar mass of [tex]CuCO_3.Cu(OH)_2[/tex] is 222 g/mol
Part 2: The mass of [tex]H_2O[/tex] and [tex]CO_2[/tex] is 18 g and 44 g respectively.
Explanation :
Part 1:
As we know that:
Atomic mass of copper, Cu = 64 g/mol
Atomic mass of carbon, C = 12 g/mol
Atomic mass of oxygen, O = 16 g/mol
Atomic mass of hydrogen, H = 1 g/mol
And we know that:
Molar mass of [tex]CuCO_3.Cu(OH)_2[/tex] = (2 × Atomic mass of Cu) + Atomic mass of C + (5 × Atomic mass of O) + (2 × Atomic mass of H)
Molar mass of [tex]CuCO_3.Cu(OH)_2[/tex] = (2 × 64) + 12 + (5 × 16) + (2 × 1)
Molar mass of [tex]CuCO_3.Cu(OH)_2[/tex] = 128 + 12 + 80 + 2
Molar mass of [tex]CuCO_3.Cu(OH)_2[/tex] = 222 g/mol
Part 2:
The balanced chemical reaction is:
[tex]CuCO_3.Cu(OH)_2(s)\rightarrow 2CuO(s)+H_2O(g)+CO_2(g)[/tex]
From the balanced chemical reaction we conclude that:
1 mole of [tex]CuCO_3.Cu(OH)_2[/tex] reacts to give 1 mole of [tex]H_2O[/tex] and 1 mole of [tex]CO_2[/tex]
Now we have to determine the mass of [tex]H_2O[/tex] and [tex]CO_2[/tex].
Mass of [tex]H_2O[/tex] = Moles of
Molar mas of [tex]H_2O[/tex] = 18 /mol
Mass of [tex]H_2O[/tex] = 1 mol × 18 g/mol = 18 g
And,
Mass of [tex]CO_2[/tex] = Moles of
Molar mas of [tex]CO_2[/tex] = 44 /mol
Mass of [tex]CO_2[/tex] = 1 mol × 44 g/mol = 44 g
Therefore, the mass of [tex]H_2O[/tex] and [tex]CO_2[/tex] is 18 g and 44 g respectively.
The molar mass of malachite has been 221.092 grams. The mass of water formed by the decomposition of 1 mole of malachite is 18 grams, and carbon dioxide has been 44 grams.
What is molar mass?
The molar mass has been the mass of each constituent element in the compound. The molar mass of malachite has been given as:
[tex]\rm CuCO_3.Cu(OH)_2=2\;Cu+C+5\;O+2\;H[/tex]
Substituting the mass of each element:
[tex]\rm CuCO_3.Cu(OH)_2=2\;(63.546)+12+5\;(16)+2\;(1)\\\\ CuCO_3.Cu(OH)_2=127.092+12+80+2\\\\ CuCO_3.Cu(OH)_2=221.092\;grams[/tex]
The molar mass of malachite has been 221.092 grams.
The moles of water and carbon dioxide decomposed in the reaction has been given by the stoichiometry law as:
1 mole of malachite decomposed of 1 mole of water and 1 mole of carbon dioxide.
The mass of 1 mole of the compound has been equivalent to the molar mass.
Thus, the mass of water formed has been 18 grams, and the mass of carbon dioxide formed has been 44 grams.
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