Answer:
9x+ 28 = 5 (x+ 8)
9x+28 = 5x+40 (use distribution property)
4x+28 = 40 (subtract 5x when bringing to the other side)
4x = 40-28 (subtract 28 when bringing to the other side)
4x = 12
x = 12/4 (divide)
x = 3
[tex]\tt Step-by-step~explanation:[/tex]
When we solve for x, we have to move all the numbers that do not contain the variable on one side, and keep x on the other side. In other words, we have to isolate the variable.
[tex]\tt Step~1:[/tex]
Equation: 9x + 28 = 5 (x + 8)
Using PEMDAS*, we will distribute the 5 to x + 8.
[tex]\tt 5(x+8)\\5x+40\\9x+28=5x+40[/tex]
[tex]\tt Step~2:[/tex]
Then, let's subtract 28 from the left side of the equation to cancel the 28, then do the same thing on the right side.
[tex]\tt 9x+28(-28)^{**}=5x+40(-28)^{**}\\9x=5x+12[/tex]
[tex]\tt Step~3:[/tex]
Subtract 5x from both sides to bring it to the left side of the equation.
[tex]\tt 9x(-5x)=5x(-5x)+12\\4x=12[/tex]
[tex]\tt Step~4:[/tex]
Finally, we can divide both sides by 4 to get x by itself.
[tex]\tt \frac{4x}{4} =x\\\frac{12}{4}=3\\ x=3[/tex]
[tex]\large\boxed{\tt Our~final~answer:~x=3}[/tex]
*PEMDAS + Parentheses first, then Exponents, then Multiplication/Division, and finally Addition/Subtraction.
**The numbers in parentheses here tell you to ADD/SUBTRACT, not multiply.
