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3. From problem 2, suppose another boy, Boy C pulls the heavy cabinet with 5 N
of force in the same direction with Boy A,
a. What will be the net force on the cabinet?
b. Will the cabinet move?
c. In what direction will the cabinet move?
?
C С
A
B​

Respuesta :

Answer:

Follows are the correct solution to this question:

Explanation:

The kids pulley in the same place, as you'll see. It implies that we already have an unstable power case, which is also referred to it as the supervisory review, since forces may not cancel. This condition will result in the creation of an unmatched net force to move or re-pay the object and is what we'll find.

First, let's discover the intensity the two guys were exercising. It is easy, it can add the strength of either of them. Size 5N + 5N = 10N  

If both of the kids' powers (10N) overcome the resistance or strength of the cabinet itself, the cabinets will pass. It succeeds to overcome the cabinet's opposition, its cabinet shifts into a boys' power.

annyksl

The net force on the cabinet can be calculated as the multiplication between the mass and acceleration that the cabinet assumes when pulled by the two boys.

As you did not present the mass and acceleration data, it is not possible to answer your questions specifically. However, you can use the information below to answer the questions.

  • The cabinet will only move if the force applied by the two boys is greater than the resistance force of the cabinet. For that, you will need to add the strength of the two boys and see if the result is superior to the strength of the cabinet.
  • If the boys' strength is greater, the cabinet will move towards the boys. If the boys' strength is equal to or less, the cabinet will not move.

More information:

https://brainly.com/question/17529892?referrer=searchResults

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