Answer:
Approximately [tex]1125\; \rm m[/tex].
Explanation:
Calculate the distance that sound would travel in [tex]1.5\; \rm s[/tex] at [tex]1500\; \rm m \cdot s^{-1}[/tex]:
[tex]s = v\cdot t = 1500\; \rm m\cdot s^{-1}\times 1.5\; \rm s = 2250\; \rm m[/tex].
Sound waves in this question here needs to:
- travel from the ship to the bottom of the sea,
- get reflected at the ocean floor, and
- travel back to the ship from the bottom of the ship.
Hence, the total distance that sound travelled in that [tex]1.5\; \rm s[/tex] would be the sum of:
- the length of the path from the ship to the ocean floor, and
- the length of the path from the ocean floor back to the ship.
Therefore, the distance [tex]2250\; \rm m[/tex] here is supposed to be approximately twice the depth of the sea at that place. The depth of the sea would thus be approximately:
[tex]\displaystyle \frac{1}{2}\times 2250\; \rm m = 1125\; \rm m[/tex].
