Answer:
[tex]y=-3x[/tex]
Step-by-step explanation:
We want to write the equation for a line that has a slope of -3 and passes through (-1, 3).
So, we can use the point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
Where m is the slope and (x₁, y₁) is a point.
Let's let (-1, 3) be (x₁, y₁) and let's substitute -3 for m. This yields:
[tex]y-3=-3(x-(-1))[/tex]
Simplify:
[tex]y-3=-3(x+1)[/tex]
Distribute on the right:
[tex]y-3=-3x-3[/tex]
Add 3 to both sides. So, our equation is:
[tex]y=-3x[/tex]
And we're done!
