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On your hand written work, write an equation and solve the problem. Below, type the three consecutive numbers from least to greatest, separated by commas.

Find three consecutive integers with a sum of -36.

~~~~~~~~~~~~~~~and~~~~~~~~~~~~~~~~~~`
A student wrote a list of six consecutive integers. If the sum of the first integer and sixth integer is 1, which integer is the least of the six integers? (Show how you got this answer in your hand written work)

Select one:
a. -2
b. 1
c. 3
d. 5

Respuesta :

nwash04

Answer:

Let  

n

be the least of the three consecutive integers. Then the integers are  

n

,

n

+

1

, and  

n

+

2

, and we have that

n

+

(

n

+

1

)

+

(

n

+

2

)

=

−

93

⇒

3

n

+

3

=

−

93

⇒

3

n

=

−

96

⇒

n

=

−

32

Substituting that into  

{

n

,

n

+

1

,

n

+

2

}

, we get the solution set  

{

−

32

,

−

31

,

−

30

}

Step-by-step explanation:

IDK WHY ITS SPREAD APART

Answer:

I answered #1 on a previous question

2) A

Step-by-step explanation:

2) So the formula for consecutive integers is x+x+1+x+2 and so on.

So we know there are 6 integers so the final would be x+5.

so the sum of the final and the first is x+5+x=1

Simplify the equation and solve

2x+5=1

2x=-4

Divide 2 on both sides

x=-2

so -2 is the least Interger of all.

Check: Use the equation x+5 since it’s the greatest,  so since x is -2 subsitute and you’ll get -2+5 you'll get 3 and 3+-2=1

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