Answer:
Valence electrons in XeCl2 = 8 + 7 + 7 = 22.
Bonding electrons = 4.
Nonbonding electrons = 18.
Explanation:
Hello.
In this case, you can see the Lewis structure on the attached picture, in which you can see that there are since xenon has 8 valance electrons and each chlorine has 7 valence electrons, the total amount of valence electrons is:
Valence electrons in XeCl2 = 8 + 7 + 7 = 22.
Moreover, since each chlorine atom is bonding with one of the eight electrons of xenon (Lewis structure), we can see there are 4 bonding electrons.
Finally, since there are six nonbonding electrons per chlorine atom and six nonbonding electrons in xenon, the overall nonbonding electrons are:
Nonbonding electrons in XeCl2 = 6 + 6 + 6 = 18.
Regards.
